Senin, 05 November 2012

Boolean Algebra With DeMorgan's Theorems

a. (A/.B.C/)/              = A//+B/+C// = A+B/+C
b. (A/+B/.C)/             = A//(B//+C/) = A(B+C/) = AB+AC/
c. (A.B.C/.D/)/           = A/+B/+C//+D// = A/+B/+C+D
d. (A+B/)/                  = A/.B// = A/.B
e. (A/.B/)/                   = A//+B// = A+B
f. (A/+C/+D/)/           = A//.C//.D// = A.C.D
g. (A(B+C/)/.D)/        = A/+B//.C///+D/ = A/+B.C/+D/

h. ((M+N/).(M/+N))/ = (M.N/)/+(M/.N)/ = (M/.N)+(M.N/)
i. (A//.B//.C/.D)/         = A///+B///+C//+D/ = A/+B/+C+D/

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